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Simplifying 0 = 8x2y(x2 + -2xy + y2) Reorder the terms: 0 = 8x2y(-2xy + x2 + y2) 0 = (-2xy * 8x2y + x2 * 8x2y + y2 * 8x2y) Reorder the terms: 0 = (8x2y3 + -16x3y2 + 8x4y) 0 = (8x2y3 + -16x3y2 + 8x4y) Solving 0 = 8x2y3 + -16x3y2 + 8x4y Solving for variable 'x'. Remove the zero: -8x2y3 + 16x3y2 + -8x4y = 8x2y3 + -16x3y2 + 8x4y + -8x2y3 + 16x3y2 + -8x4y Reorder the terms: -8x2y3 + 16x3y2 + -8x4y = 8x2y3 + -8x2y3 + -16x3y2 + 16x3y2 + 8x4y + -8x4y Combine like terms: 8x2y3 + -8x2y3 = 0 -8x2y3 + 16x3y2 + -8x4y = 0 + -16x3y2 + 16x3y2 + 8x4y + -8x4y -8x2y3 + 16x3y2 + -8x4y = -16x3y2 + 16x3y2 + 8x4y + -8x4y Combine like terms: -16x3y2 + 16x3y2 = 0 -8x2y3 + 16x3y2 + -8x4y = 0 + 8x4y + -8x4y -8x2y3 + 16x3y2 + -8x4y = 8x4y + -8x4y Combine like terms: 8x4y + -8x4y = 0 -8x2y3 + 16x3y2 + -8x4y = 0 Factor out the Greatest Common Factor (GCF), '8x2y'. 8x2y(-1y2 + 2xy + -1x2) = 0 Factor a trinomial. 8x2y((-1y + x)(y + -1x)) = 0 Ignore the factor 8.Subproblem 1
Set the factor 'x2y' equal to zero and attempt to solve: Simplifying x2y = 0 Solving x2y = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x2y = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.Subproblem 2
Set the factor '(-1y + x)' equal to zero and attempt to solve: Simplifying -1y + x = 0 Reorder the terms: x + -1y = 0 Solving x + -1y = 0 Move all terms containing x to the left, all other terms to the right. Add 'y' to each side of the equation. x + -1y + y = 0 + y Combine like terms: -1y + y = 0 x + 0 = 0 + y x = 0 + y Remove the zero: x = y Simplifying x = ySubproblem 3
Set the factor '(y + -1x)' equal to zero and attempt to solve: Simplifying y + -1x = 0 Reorder the terms: -1x + y = 0 Solving -1x + y = 0 Move all terms containing x to the left, all other terms to the right. Add '-1y' to each side of the equation. -1x + y + -1y = 0 + -1y Combine like terms: y + -1y = 0 -1x + 0 = 0 + -1y -1x = 0 + -1y Remove the zero: -1x = -1y Divide each side by '-1'. x = y Simplifying x = ySolution
x = {y, y}
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